Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as: illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
Note: m and n will be at most 100.
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
if(obstacleGrid.length < 1 && obstacleGrid[0].length < 1) {
return 0;
}
int row = obstacleGrid.length;
int col = obstacleGrid[0].length;
int[][] rst = new int[row][col];
rst[0][0] = obstacleGrid[0][0] == 1 ? 0 : 1;
for(int i = 1; i < col; i++) {
rst[0][i] = (obstacleGrid[0][i] == 1 || rst[0][i - 1] == 0) ? 0 : 1;
}
for(int i = 1; i < row; i++) {
rst[i][0] = (obstacleGrid[i][0] == 1 || rst[i - 1][0] == 0) ? 0 : 1;
}
for(int i = 1; i < row; i++) {
for(int j = 1; j < col; j ++) {
if(obstacleGrid[i][j] == 1) {
rst[i][j] = 0;
} else {
rst[i][j] = rst[i - 1][j] + rst[i][j - 1];
}
}
}
return rst[row - 1][col - 1];
}
}