Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
For example, given candidate set 10,1,2,7,6,1,5 and target 8,
A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
public class Solution {
public List<List<Integer>> combinationSum2(int[] candidates, int target) {
List<List<Integer>> rst = new ArrayList<List<Integer>>();
Arrays.sort(candidates);
helper(rst, new ArrayList<Integer>(), candidates, 0, target);
return rst;
}
private void helper(List<List<Integer>> rst, List<Integer> item, int[] candidates, int start, int target) {
if(target < 0) {
return;
}
if(target == 0) {
rst.add(new ArrayList<Integer>(item));
return;
}
for(int i = start; i < candidates.length; i++) {
if(i > start && candidates[i] == candidates[i - 1]) {
continue;
}
item.add(candidates[i]);
helper(rst, item, candidates, i + 1, target - candidates[i]);
item.remove(item.size() - 1);
}
}
}