Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_____6______
/ \
___2__ ___8__
/ \ / \
0 _4 7 9
/ \
3 5
For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
http://articles.leetcode.com/2011/07/lowest-common-ancestor-of-a-binary-search-tree.html
public class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if(root == null || p == null || q == null) {
return null;
}
if(Math.max(p.val, q.val) < root.val) {
return lowestCommonAncestor(root.left, p, q);
} else if(Math.min(p.val, q.val) > root.val) {
return lowestCommonAncestor(root.right, p, q);
} else {
return root;
}
}
}