Sqrt(x)

Implement int sqrt(int x).

Compute and return the square root of x.

Java

http://bangbingsyb.blogspot.com/2014/11/leetcode-sqrtx.html

public class Solution {
    public int mySqrt(int x) {
        if(x == 0) {
            return 0;
        }

        int left = 1;
        int right = x / 2 + 1;

        while(left <= right) {
            int mid = (right - left) / 2 + left;
            if(mid == x / mid) {
                return mid;
            } else if(x / mid > mid) {
                left = mid + 1;
            } else {
                right = mid - 1;
            }
        }
        return right;
    }
}