Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
But the following is not:
1
/ \
2 2
\ \
3 3
public class Solution {
public boolean isSymmetric(TreeNode root) {
if(root == null) {
return true;
}
return isSymmetric(root.left, root.right);
}
public boolean isSymmetric(TreeNode left, TreeNode right) {
if(left == null && right == null) {
return true;
} else if(left != null && right != null && left.val == right.val) {
return isSymmetric(left.left, right.right) && isSymmetric(left.right, right.left);
} else {
return false;
}
}
}