Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
For example:
Given the following binary tree,
1 <---
/ \
2 3 <---
\ \
5 4 <---
You should return [1, 3, 4].
public class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> rst = new ArrayList<Integer>();
if(root == null) {
return rst;
}
LinkedList<TreeNode> queue = new LinkedList<TreeNode>();
queue.add(root);
while(queue.size() > 0) {
int size = queue.size();
for(int i = 0; i < size; i++) {
TreeNode node = queue.poll();
if(i == 0) {
rst.add(node.val);
}
if(node.right != null) {
queue.add(node.right);
}
if(node.left != null) {
queue.add(node.left);
}
}
}
return rst;
}
}