Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
For example, given candidate set 2,3,6,7 and target 7,
A solution set is:
[7]
[2, 2, 3]
public class Solution {
public List<List<Integer>> combinationSum(int[] candidates, int target) {
List<List<Integer>> rst = new ArrayList<List<Integer>>();
Arrays.sort(candidates);
helper(rst, new ArrayList<Integer>(), candidates, 0, target);
return rst;
}
private void helper(List<List<Integer>> rst, List<Integer> item, int[] candidates, int start, int target) {
if(target < 0) {
return;
}
if(target == 0) {
rst.add(new ArrayList<Integer>(item));
return;
}
for(int i = start; i < candidates.length; i++) {
item.add(candidates[i]);
helper(rst, item, candidates, i, target - candidates[i]);
item.remove(item.size() - 1);
}
}
}